How to determine 32 or 64 bit architecture of Windows using Java?

How to determine 32 or 64 bit architecture of Windows using Java?

You can determine whether the Windows operating system is running on a 32-bit or 64-bit architecture using Java by reading the system properties. Here's how you can do it:

public class WindowsArchitecture {
    public static void main(String[] args) {
        String osArch = System.getProperty("os.arch");
        
        if (osArch.contains("64")) {
            System.out.println("64-bit Windows");
        } else {
            System.out.println("32-bit Windows");
        }
    }
}

In this code:

  1. We use System.getProperty("os.arch") to retrieve the system architecture information.

  2. We check if the retrieved architecture string contains "64". If it does, we conclude that it's a 64-bit Windows operating system. Otherwise, it's a 32-bit Windows operating system.

When you run this code on a Windows machine, it will print either "64-bit Windows" or "32-bit Windows" based on the architecture of the operating system.

Keep in mind that this method checks the architecture of the operating system where the Java program is running, not the architecture of the Java Virtual Machine (JVM) itself.

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