In this tutorial, we'll learn how to assign the subsequent rows of a matrix to the elements of its first row.
Given a matrix (2D list), assign each subsequent row of the matrix as a value to the corresponding element in the first row, resulting in a dictionary where keys are the elements of the first row and values are the rest of the rows as lists.
For instance, consider the matrix:
matrix = [ ['apple', 'banana', 'orange'],
[10, 20, 30],
['red', 'yellow', 'orange']
]
We want to transform it to:
{
'apple': [10, 'red'],
'banana': [20, 'yellow'],
'orange': [30, 'orange']
}
We can achieve this using a combination of dictionary comprehension and the zip function:
zip function to transpose the matrix, which essentially groups columns together.Here's the implementation:
def assign_rows_to_first_row_elements(matrix):
# Transpose the matrix to group columns together
transposed = list(zip(*matrix))
# Create a dictionary with the first row elements as keys
# and the subsequent rows as their corresponding values
return {col[0]: list(col[1:]) for col in transposed}
matrix = [
['apple', 'banana', 'orange'],
[10, 20, 30],
['red', 'yellow', 'orange']
]
result = assign_rows_to_first_row_elements(matrix)
print(result) # Output: {'apple': [10, 'red'], 'banana': [20, 'yellow'], 'orange': [30, 'orange']}
zip(*matrix) function transposes the matrix. It effectively converts rows into columns.This tutorial provided a method to transform a matrix into a dictionary by assigning the subsequent rows as values to the elements of the first row. This kind of transformation can be useful in various data processing scenarios where a matrix representation needs to be converted into a key-value mapping.
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